2v^2+9v-110=0

Solution for 2v^2+9v-110=0 equation:

2v^2+9v-110=0

a = 2; b = 9; c = -110;
Δ = b2-4ac
Δ = 92-4·2·(-110)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-31}{2*2}=\frac{-40}{4}
=-10
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+31}{2*2}=\frac{22}{4}
=5+1/2
$